How much heat must be removed from 0.175 kg of water to lower its temperature from 24.3°C to 5.00°C? (Unit = J)

Respuesta :

Answer:

14185.5J

Explanation:

Thermal energy can be calculated using the formula

Q = mcT where

Q is the amount of thermal energy in J

m is the mass in kg

c is the specific heat capacity in J/kg/C

T is the change in Temperature in C.

Hence by applying this formula, we get:

Q = (0.175)(4200)(24.3 - 5.00)

Q = 14185.5 J