Respuesta :
Answer:
Therefore the one combination is
200 tickets of Children and 100 tickets of Adult.
Therefore Total Amount will be given as
[tex]5x+10y=2000[/tex] ..........As Required
Step-by-step explanation:
Given:
Children's tickets cost = 5$ (per ticket)
Adult tickets cost = 10$ (per ticket)
Total Amount = 2000$
Let the number of Children's Ticket be " x "
and the number of Adult's Ticket be " y "
Therefore,
Total cost for Children's Ticket will be = [tex]5\times x[/tex]
Total cost for Adult's Ticket will be = [tex]10\times y[/tex]
Therefore Total Amount will be given as
[tex]5x+10y=2000[/tex] ...........As Required
So there are many combinations to get 2000$ one of the as follow
Children's tickets cost = 1000$
∴ [tex]5x = 1000\\x=\dfrac{1000}{5}=200\ tickets[/tex]
Adult's tickets cost = 1000$
[tex]10x = 1000\\x=\dfrac{1000}{10}=100\ tickets[/tex]
Therefore the one combination is
200 tickets of Children and 100 tickets of Adult.
Answer:
One combination would be 100 adults tickets and 200 children tickets.
Step-by-step explanation:
Given:
Cost of children's ticket = $5
Cost of adult's ticket = $10
The theater wants to make $2000
To find one combination of children and adult tickets that will make $2000.
Solution:
Let us assume a combination that:
Total money made from children tickets be = $1000
Total money made by adults tickets will be = [tex]\$2000-\$1000[/tex] = $1000
Thus, number of children's tickets will be:
⇒ [tex]\frac{total\ money\ from\ children\ tickets}{Cost\ of each children ticket}[/tex]
⇒ [tex]\frac{\$1000}{\$10}[/tex]
⇒ 200
Thus, number of adult tickets will be:
⇒ [tex]\frac{total\ money\ from\ adult\ tickets}{Cost\ of each adult ticket}[/tex]
⇒ [tex]\frac{\$1000}{\$5}[/tex]
⇒ 100
Thus, one combination would be 100 adults tickets and 200 children tickets.
