Answer:
the programmer's wage before the change was $80.
Step-by-step explanation:
i) let the original wages be $x.
ii) the new wages after an increase of 10% are $88.
iii) therefore we can write $x + [tex]\frac{10}{100}[/tex]x = 1.1 x = 88
therefore x = [tex]\frac{88}{1.1} = 80[/tex]
therefore the programmer's wage before the change was $80.
