Respuesta :

[tex](3y - 4 y +1)+(-y)^2+y-2[/tex]  [tex]=(y+1)(y-1)[/tex]

Step-by-step explanation:

Given that

[tex](3y - 4 y +1)+(-y)^2+y-2[/tex]

[tex]=(-y+1) + y^{2} +y-2[/tex]

[tex]=-y +1+y^{2} +y -2[/tex]

[tex]=y^{2} - 1[/tex]

[tex]= y^2 -(1)^2[/tex]

[tex]=(y+1)(y-1)[/tex]

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