Answer:
Mass of solute, LiCl = 8.60g
Mass of solvent, H₂O = 57.4 g
Explanation:
Solution density = Solution mass / Solution volume
1.0736 g/mL = 66 g / Solution volume
66 g / 1.0736 g/mL = 61.47 mL
We know solution's molarity, so with this data we know that 3.30 moles of solute (LiCl) are contained in 1 L of solution (1000 mL)
Let's make the rule of three:
1000 mL contain 3.30 moles of LiCl
61.47 mL would contain (61.47 mL . 3.30 mol) / 1000 mL = 0.203 moles of LiCl
We can find out the mass of solute with the moles. Let's do it!
0.203 mol . 42.39 g/mol = 8.60 g of LiCl.
Total mass = Mass of solvent + Mass of solute
Let's find out the mass of solvent, to finish the problem
66 g = Mass of solvent + 8.60 g
66 g - 8.60 g = Mass of solvent → 57.4 g
Answer:
The solute (LiCl) has a mass of 8.605 grams
The solvent has a mass of 57.395 grams
Explanation:
Step 1: Data given
Molarity of LiCl= 3.30 M
Densit = 1.0736 g/mL
Mass of the solution = 66.0 grams
Step 2: Calculate volume of LiCl solution
Volume = mass / density
Volume = 66.0 grams / 1.0736 g/mL
Volume = 61.5 mL = 0.0615 L
Step 3: Calculate moles of LiCl
Moles = molarity * volume
Moles = 3.30 M * 0.0615 L
Moles = 0.203 moles
Step 4: Calculate mass of LiCl (solute)
Mass = moles * molar mass
Mass LiCl = 0.203 moles * 42.39 g/mol
Mass LiCl = 8.605 grams
Step 5: Calculate mass solvent
Mass solvent = mass solution - mass solute
Mass solvent = 66.0 g - 8.605
Mass solvent = 57.395
The solute (LiCl) has a mass of 8.605 grams
The solvent has a mass of 57.395 grams
