Answer:
We have two possible values for the second tuning fork
443Hz and 337Hz
Explanation:
When two waves of slightly different frequency interfere, they produce beats and the frequency of the beats (fb) is:
[tex]f_{b}=\mid f_{1}-f_{2}\mid [/tex]
with f1 the frequency of the first tuning fork and f2 the frequency of the second tuning fork, so we should solve
[tex]3=\440-f_{2}\mid [/tex]
note that it is the absolute vale of the rest between f1 and f2 so we have two equations and two possible values:
[tex]3=440-f_{2} [/tex]
[tex]f_{2}=337Hz [/tex]
and
[tex]-3=440-f_{2} [/tex]
[tex]f_{2}=443Hz [/tex]
