Listed below are the annual tuition amounts of the 10 most expensive colleges in a country for a recent year.
What does this "Top 10" list tell about the population of all that country's college tuitions?
Find the mean, midrange, median, and mode of the data set. Round to two decimal places as needed.

$52,384 $54,079 $52,762 $54,364 $52,584

$53,987 $53,108 $51,588 $50,554 $53,987

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dfbustos dfbustos · Answer 1 · 2020-01-29T09:10:17+01:00

Answer:

[tex]\bar X = \frac{52384 +54079 +52762 +54364 +52584+53987 +53108 +51588 +50554 +53987}{10}=52939.7[/tex]

[tex] Mode= 53987[/tex]

[tex] Median = \frac{52762+53108}{2}=52935[/tex]

[tex] Midrange=\frac{50554+54364}{2}=52459[/tex]

Step-by-step explanation:

We can calculate the mean with the following formula:

[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

And if we replace the values given we got:

[tex]\bar X = \frac{52384 +54079 +52762 +54364 +52584+53987 +53108 +51588 +50554 +53987}{10}=52939.7[/tex]

The mode is the most repeated value and for this case with a frequency of 2 the mode is:

[tex] Mode= 53987[/tex]

In order to find the median we need to order the dataset on increasing way like this:

50554, 51588, 52384 ,52584, 52762

53108, 53987 , 53987 , 54079, 54364

Since we have 10 values an even number the median is calculated from the average between positions 5 and 6 on the data ordered, and we got:

[tex] Median = \frac{52762+53108}{2}=52935[/tex]

The mid range is defined like this:

[tex] Midrange = \frac{Max +Min}{2}[/tex]

And if we replace we got:

[tex] Midrange=\frac{50554+54364}{2}=52459[/tex]