Answer:
-375.9_KJ/(mol)
Explanation:
H(T2 ) ≈ H(T1)+CPΔT
Specific heat of Carbon is 0.71 J/g K.
At 283.15 the heat capacity is 37.12 J/(mol*K)
Kirchhoff's law
H(T2 ) ≈ H(T1)+CPΔT
Where
H(T1) and H(T2 ) are the heat of formation of CO2 at temperatures T1 and T2
CP is the heat capacity
Thus we have and ΔT is the temperature change
H(T2 ) ≈ -393.51×10^3+CP×(500-25)
= -393.51×10^3+37.12×(500-25)
= -375878 J/(mol)
= -375.9KJ/(mol)
