Answer: 500 coloumb of charge is transferred in this event.
Explanation:
We are given:
According to mole concept:
1 mole of an atom contains [tex]6.022\times 10^{23}[/tex] number of particles.
We know that:
Charge on 1 electron = [tex]1.6\times 10^{-19}C[/tex]
Charge on 1 mole of electrons = [tex]1.6\times 10^{-19}\times 6.022\times 10^{23}=9.6352\times 10^4C[/tex]
To calculate the charge transferred, we use the equation:
[tex]I=\frac{q}{t}[/tex]
where,
I = current passed = [tex]2.5\times 10^4A[/tex]
q = total charge = ?
t = time = 20 ms =0.02 s (1 ms =0.001 s)
Putting values in above equation, we get:
[tex]2.5\times 10^4A=\frac{q}{0.02s}\\\\q=500C[/tex]
Thus 500 coloumb of charge is transferred in this event.
