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The gage pressure in a liquid at a depth of 3 m is read to be 48 kPa. Determine the gage pressure in the same liquid at a depth of 9 m.
The gage pressure in the same liquid at a depth of 9 m is__________ kPa.

Respuesta :

Answer: 144kpa

Explanation:

pressure density =p

The Gage pressure (P1)=48kpa

The height (h1)=3m

The Gage pressure (P2)=?

The height (h2)=9m

P=p * g * h

P1/P2=p * g * h1/p * g * h2

Cancelling out similar terms:

Therefore, P1/P2=h1/h2

P2=P1*h2/h1

Hence, P2=48*9/3=144kpa.

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