Answer:
Explanation:
[tex]C_{water}[/tex] = 4190 J/kg.K
[tex]C_{Al}[/tex] = 910 J/Kg. K
[tex]m_{Al}[/tex] = 1.50 kg
[tex]m_{water}[/tex] = 1.80 kg
[tex]Q_{added} = Q_{Al} + Q_{water}[/tex]
[tex]=m_{Al} C_{Al}[/tex]ΔT + [tex]m_{water} C_{water}[/tex]ΔT
= (1.50)(910)(85.0-20)+(1.80)(4190)(85.0-20)
= 578,955 J
= 579 kJ
