Answer:
Step-by-step explanation:
Alright, lets get started.
The given equation is :
[tex]e^{3x+6} =8[/tex]
taking log on both side
[tex]lne^{3x+6}=ln8[/tex]
[tex](3x+6)lne=ln8[/tex]
Plugging the value of ln e as 1
[tex]3x+6=ln8[/tex]
Subtracting 6 in both sides
[tex]3x+6-6=ln8-6[/tex]
[tex]3x=ln8-6[/tex]
Dividing 3 in both sides
[tex]x=\frac{ln8-6}{3}[/tex] ........................ Answer
Hope it will help :)
