A particular 3.0 L solution contains 2.5 mmol (millimoles) of a substance. What is the concentration of this solution in number of molecules per cubic meter? g

Respuesta :

Answer: 0.83mol/m3

Explanation:

Number of mole = 2.5 mmol = 0.0025mol

Recall

1L = 0.001m3

Therefore 3L = 3x0.001 = 0.003m3

0.003m3 contains 0.0025mol

Therefore, 1m3 will contain = 0.0025/0.003 = 0.83mol

The concentration in mol/m3 is 0.83mol/m3

The concentration of this solution in number of molecules per cubic meter is equal to 5 x 10^23 molecules.

Calculation of molecules

To calculate the amount of molecules present in a given substance, one must use Avogadro's constant, which corresponds to:

                                     [tex]6 \times 10 ^{23}molecules =1mol[/tex]

For this question, we must first calculate the molarity, so that:

                                               [tex]\frac{2.5 \times 10^{-3}mol}{xmol} =\frac{3L}{1L}[/tex]

                                            [tex]x = 0.83 \times 10^{-3} mol/L[/tex]

After that, you must convert the unit of volume to cubic centimeters, that is, milliliters, so that:

                                   [tex]0.83 \times 10^{-3} mol/L = 0.83 mol/ml[/tex]

Finally, just multiply the value obtained by the avogadro constant:

                                [tex]0.83 \times 6\times 10^{23}= 5 \times 10^{23} molecules[/tex]

So, the concentration of this solution in number of molecules per cubic meter is equal to 5 x 10^23 molecules.

Learn more about mole calculation in: brainly.com/question/2845237