Respuesta :
Answer:
Nt=10 (m=4,n=6)
Step-by-step explanation:
we have that m = amount of time used by the large washing machine to wash a load of clothes and n = amount of time used by the small washing machine to wash a load of clothes, so
[tex]m=\frac{Tt}{Tpm}=\frac{2h}{\frac{1h}{2}}=4\\n=\frac{Tt}{Tpn}=\frac{2h}{\frac{1h}{3}}=6[/tex]
Nt=m+n=10
where Tt = time frame, Tpm= m' time frame, Tpn = n' time frame and Nt = total number of charges
Answer: Total laundry done in 2hours=110
Step-by-step explanation:
Let m be large washing machines
Let n be small washing machines
Load of laundry for large machine=30mins
Load of laundry in small machine=20 mins
2 hours laundry =2×60=120mins
For m in 2hrs=120/30=4
For n in 2hrs=120/20=6
m loads in 2hrs=4m
n loads in 2hrs=6n
1st statement:n=3m
Substituting
4m+6(3)=x
4m+18m=x
X=22m
Value of m cannot be determined because statement 1 is insufficient
From the 2nd statement: 2m+3n=55
Multiply both sides by2
4m+6n=110