Answer: The equilibrium concentration of bromine gas is 0.00135 M
Explanation:
We are given:
Initial concentration of chlorine gas = 0.0300 M
Initial concentration of bromine monochlorine = 0.0200 M
For the given chemical equation:
[tex]2BrCl\rightleftharpoons Br_2+Cl_2[/tex]
Initial: 0.02 0.03
At eqllm: 0.02-2x x 0.03+x
The expression of [tex]K_c[/tex] for above equation follows:
[tex]K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}[/tex]
We are given:
[tex]K_c=0.141[/tex]
Putting values in above equation, we get:
[tex]0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135[/tex]
Neglecting the value of x = -0.96 because, concentration cannot be negative
So, equilibrium concentration of bromine gas = x = 0.00135 M
Hence, the equilibrium concentration of bromine gas is 0.00135 M
