Respuesta :
Answer:
The answer to your question is ΔHrxn = 0 kJ
Explanation:
Process
1.- Multiply Equation 1 by 2
2C(coal) + 2H₂O ⇒ 2CO (g) + 2H₂ ΔH rxn = 259.4 kJ
2.- Sum equation 2
CO(g) + H₂O ⇒ CO₂ (g) + H₂ (g) ΔHrxn = -41 kJ
Result
2C + 3H₂O + CO ⇒ 2CO + 3H₂ + CO₂ ΔHrxn = 218.4 kJ
Simplification
2C + 3H₂O ⇒ CO + 3H₂ + CO₂
3.- Sum equation 3
CO(g) + 3H₂ (g) ⇒ CH₄ (g) + H₂O (g) ΔHrxn = -218.4 kJ
Result
2C + 3H₂O + 3H₂ + CO ⇒ CO + 3H₂ + CO₂ + CH₄ + H₂O
Simplification
2C + 2H₂O ⇒ CO₂ + CH₄ ΔHrxn = 0 kJ
The heat of reaction, ΔH°rxn, for overall reaction in coal gasification for the production of methane, CH₄ is 12.4 kJ
From the question,
We are to determine the heat of reaction for overall reaction for the production of methane in coal gasification
The equation for the reaction of coal gasification is
2C(coal) + 2H₂O → CO₂ + CH₄
From the question,
We have the following equations of reactions
(1) C(coal) + H₂O(g) → CO(g) + H₂(g) ΔH°rxn = 129.7 kJ
(2) CO(g) + H₂O(g) → CO₂(g) + H₂(g) ΔH°rxn = -41 kJ
(3) CO(g) + 3H₂(g) → CH₄(g) + H₂O(g) ΔH°rxn = -206 kJ
Multiply (1) by 2 to get
(4) 2C(coal) + 2H₂O(g) → 2CO(g) + 2H₂(g) ΔH°rxn = 259.4 kJ
Now, adding equations (2), (3), and (4), we get
(2) CO(g) + H₂O(g) → CO₂(g) + H₂(g) ΔH°rxn = -41 kJ
(3) CO(g) + 3H₂(g) → CH₄(g) + H₂O(g) ΔH°rxn = -206 kJ
(4) 2C(coal) + 2H₂O(g) → 2CO(g) + 2H₂(g) ΔH°rxn = 259.4 kJ
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2C(coal) + 2H₂O(g) → CH₄(g) + CO₂(g) ΔH°rxn = 12.4 kJ
Hence, the heat of reaction, ΔH°rxn, for overall reaction in coal gasification for the production of methane, CH₄ is 12.4 kJ
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