Answer:
y = -1/3x + 2
Step-by-step explanation:
Two points of the inequality
(0,2)
(3,1)
Gradient of the inequality
[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]\frac{1-2}{3-0}\\\frac{-1}{3}[/tex]
Substitute one of the points into y = -1/3x + c to find c
y = -1/3x + c at (0,2)
2 = -1/3(0) + c
2 = 0 + c
2 = c
y = -1/3x + c at (3,1)
1 = -1/3(3) + c
1 = -1 + c
1 + 1 = c
2 = c
y = -1/3x + c
Replace c with 2
y = -1/3x + 2
