Answer:
He travel for 2 h at the first part and 2 h for the second part.
Explanation:
given information:
business trip's distance, [tex]s_{tot}[/tex] = 214 miles
v₁ = 53 mph
v₂ = 54 mph
t₁ = t
t₂ = 4 - t
now lets find the distance of each speed
s₁ = v₁ t₁ = 53 t₁
s₂ = v₂ t₂ = 54 t₂
[tex]s_{tot}[/tex] = s₁ + s₂
214 = 53 t₁ + 54 t₂
214 = 53t + 54 (4-t)
214 = 53t + 216 - 54 t
t = 216 - 214
= 2 h
t₁ = t = 2 h
t₂ = 4 - t = 4 -2 = 2h
