Answer:
D.141 g
Explanation:
Given that:-
Mass of ethylene = 45.0 g
Molar mass of ethylene = 28.05 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{45.0\ g}{28.05\ g/mol}[/tex]
[tex]Moles= 1.60\ mol[/tex]
According to the reaction below:-
[tex]C_2H_4+3O_2\rightarrow 2CO_2+2H_2O[/tex]
1 mole of ethylene produces 2 moles of carbon dioxide
So,
1.60 mole of ethylene produces 2*1.60 moles of carbon dioxide
Moles of carbon dioxide = 3.2 mol
Molar mass of carbon dioxide = 44.01 g/mol
Mass = Moles*Molar mass = 3.2 mol x 44.01 g/mol = 141 g
D.141 g of carbon dioxide will be produced
