Explanation:
It is known that formula for area of a sphere is as follows.
A = [tex]4 \pi r^{2}[/tex]
= [tex]4 \times 3.14 \times (0.50 m)^{2}[/tex]
= 3.14 [tex]m^{2}[/tex]
[tex]T_{a}[/tex] = (27 + 273.15) K = 300.15 K
T = (77 + 273.15) K = 350.15 K
Formula to calculate the net charge is as follows.
Q = [tex]esA(T^{4} - T^{4}_{a})[/tex]
where, e = emissivity = 0.85
s = stefan-boltzmann constant = [tex]5.6703 \times 10^{-8} Wm^{-2} K^{-4}[/tex]
A = surface area
Hence, putting the given values into the above formula as follows.
Q = [tex]esA(T^{4} - T^{4}_{a})[/tex]
= [tex]0.85 \times 5.6703 \times 10^{-8} Wm^{-2} K^{-4} \times 3.14 \times ((350.15)^{4} - (300.15)^{4})[/tex]
= 1046.63 W
Therefore, we can conclude that the net flow of energy transferred to the environment in 1 second is 1046.63 W.
