Answer:
(A) Equation will be [tex]v=v_msin\omega t=0.75sin(18840t)[/tex]
(B) RMS value of voltage will be 0.530 volt
Explanation:
We have given peak to peak voltage of ac wave = 1.5 volt
Peak to peak voltage of ac wave is equal to 2 times of peak voltage
So [tex]2v_{peak}=1.5volt[/tex]
[tex]v_{peak}=\frac{1.5}{2}=0.75volt[/tex]
Frequency of ac wave is given f = 3 kHz
So angular frequency [tex]\omega =2\pi f[/tex] = 2×3.14×3000 = 18840 rad/sec
So expression of equation will be [tex]v=v_msin\omega t=0.75sin(18840t)[/tex] ( As phase difference is 0 )
Now we have to find the rms value of voltage
So rms voltage will be equal to [tex]v_{rms}=\frac{v_{peak}}{\sqrt{2}}=\frac{0.75}{1.414}=0.530volt[/tex]
