A machine gun fires 50-g bullets at the rate of 4 bullets per second. The bullets leave the gun at a speed of 1000 m/s. What is the average recoil force experienced by the machine gun?

Question

contestada

Respuesta :

aristeus aristeus · Answer 1 · 2020-01-28T07:43:53+01:00

Answer:

Average recoil force experienced by machine will be 200 N

Explanation:

We have give mass of each bullet m = 50 gram = 0.05 kg

There are 4 bullets

So mass of 4 bullets = 4×0.05 = 0.2 kg

Initial speed of the bullet u = 0 m/sec

And final speed of the bullet v = 1000 m/sec

So change in momentum [tex]P=m(v-u)=0.2\times (1000-0)=200kgm/sec[/tex]

Time is given per second so t = 1 sec

We know that force is equal to rate of change of momentum

So force will be equal to [tex]F=\frac{200}{1}=200N[/tex]

So average recoil force experienced by machine will be 200 N

raphealnwobi raphealnwobi · Answer 2 · 2021-12-02T12:59:59+01:00

The average recoil force experienced by the machine gun is 100N.

The impulse-momentum theorem states that the impulse applied to an object will be equal to the change in its momentum.

Force (F) * change in time (Δt) = change in momentum = mass (m) * velocity (v)

FΔt = mv

m = 50 g = 0.05 kg

F = mv / Δt

F = (0.05kg * 1000 m/s * 4 bullets)/ 1 second

F = 100 N

The average recoil force experienced by the machine gun is 100N.

Find out more at: https://brainly.com/question/19284095