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A solution has a pH of 11.00. Calculate the [H3O+] of the solution.

[H3O+]= 4.8x10-3

[H3O+]= 1.0x10-11

[H3O+]= 3.8x10-13

cannot be calculated with the information given

[H3O+]= 1.0x10-8

Respuesta :

anfabba15

Answer:

[H₃O⁺] → 1×10¹¹

Second option

Explanation:

pH = - log [H₃O⁺]

So, 10^⁻pH =  [H₃O⁺]

pH = 11

10⁻¹¹ =  [H₃O⁺] → 1×10¹¹

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