Answer:
Therefore,
The three points for the line y = 0.5x - 7 ....( Red line )
point A( x₁ , y₁) ≡ ( 0 ,-7) (blue color point on the graph)
point B( x₂ , y₂) ≡ (14 , 0) (green color point on the graph)
point C(x₃ , y₃ ) ≡ (2 , -6) (purple color point on the graph)
The Graph is attached below..
Step-by-step explanation:
Given:
[tex]y = 0.5x - 7[/tex] ........... equation of a line
Let the points be point A, point B,and point C
To Find:
point A( x₁ , y₁) ≡ ?
point B( x₂ , y₂) ≡ ?
point C(x₃ , y₃ ) ≡ ?
Solution:
For Drawing a graph we require minimum two points but we will have here three points.
For point A( x₁ , y₁)
Put x = 0 in the given equation we get
y = 0.5 × 0 -7
y = -7
∴ point A( x₁ , y₁) ≡ ( 0 ,-7)
For point B( x₂ , y₂)
Put y= 0 in the given equation we get
0 = 0.5x -7
∴ [tex]x=\dfrac{7}{0.5} \\\\x=14[/tex]
∴ point B( x₂ , y₂) ≡ (14 , 0)
For point C(x₃ , y₃ )
Put x = 2 in the given equation we get
y = 0.5 × 2 - 7
y = -6
y = - 6
∴ point C(x₃ , y₃ )≡ (2 , -6)
Therefore,
The three points for the line y = 0.5x - 7 ....( Red line )
point A( x₁ , y₁) ≡ ( 0 ,-7) (blue color point on the graph)
point B( x₂ , y₂) ≡ (14 , 0) (green color point on the graph)
point C(x₃ , y₃ ) ≡ (2 , -6) (purple color point on the graph)
The Graph is attached below..
