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a 500 kg car is accelerated from rest by a force of 2000 N for a displacement of 400m. what is the speed of the car at the end of 400 M?

Respuesta :

MathPhys

Answer:

57 m/s

Explanation:

Use Newton's second law to find the acceleration.

F = ma

2000 N = (500 kg) a

a = 4 m/s²

Given:

Δx = 400 m

v₀ = 0 m/s

a = 4 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (4 m/s²) (400 m)

v ≈ 57 m/s

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