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A rotating flywheel can be used as a method to store energy. If it is required that such a device be able to store up to a maximum of 1.00 ´ 106 J when rotating at 400 rad/s, what moment of inertia is required?

options:

1)

50 kg×m2

2)

25 kg×m2

3)

12.5 kg×m2

4)

6.3 kg×m2

5)

5.4 kg×m2

Respuesta :

Answer:

(3).I = 12.5 kg.m²

Explanation:

Given that

maximum stored energy E

E= 1 x 10⁶ J

Angular speed ,ω = 400 rad/s

We know that energy stored in flywheel given as

[tex]E=\dfrac{1}{2}I\omega^2[/tex]

I=Moment of inertia of the flywheel

Now by putting the values

[tex]10^6=\dfrac{1}{2}\times I\times 400^2[/tex]

[tex]I=\dfrac{2\times 10^6}{400^2}[/tex]

I = 12.5 kg.m²

Therefore the answer will be (3).

I = 12.5 kg.m²

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