Respuesta :
This is an incomplete Question.
The complete question is:
Carbon disulfide gas and oxygen gas react to form sulfur dioxide gas and carbon dioxide gas. What volume of carbon dioxide would be produced by this reaction if 2.4 m3 of carbon disulfide were consumed? Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.
Answer: [tex]2.40m^3[/tex]
Explanation:
The balanced chemical reaction will be:
[tex]CS_2+3O_2\rightarrow 2SO_2+CO_2[/tex]
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Given volume= [tex]2.4m^3=2400L[/tex] [tex]1m^3=1000L[/tex]
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar Volume}}=\frac{2400L}{22.4L}=107moles[/tex]
According to stoichiometry:
1 mole of carbon disulfide gives = 1 mol of carbon dioxide
Thus 107 moles of carbon disulfide gives=[tex]\frac{1}{1}\times 17=107moles[/tex]
Volume of carbon dioxide =[tex]moles\times {\text {Molar Volume}}=107mol\times 22.4L/mol=2396.8L=2.40m^3[/tex]
Thus the volume of carbon dioxide produced by this reaction if [tex]2.40m^3[/tex] of carbon disulfide were consumed.
The volume of SO2 produced at the end of the reaction is 19mL
Data;
- volume of carbon disulfide = 9.5ml
If a reaction occurs in gaseous phase, then we can apply the vol-vol analysis just like mole - mole analysis since they're proportional
from Ideal gas equation;
[tex]pv = nRT\\v \alpha n[/tex]
Equation of Reaction
To solve this problem effectively, let's write down the equation of reaction.
[tex]Cs + 3O_2 \to 2SO_2 + CO_2\\[/tex]
9.5 - - - Initial
0 - 2*9.5 9.5 After
The volume of SO2 produced at the end of the reaction is 19mL
Learn more on ideal gas equation here;
https://brainly.com/question/12873752
