Answer:
20 cm to the right of the center or 20+50 = 70 cm from the left side.
Explanation:
The length of meter stick is 1 m = 100 cm
Balance point on 50 cm
From the center the 20 N weight is 50-20 = 30 cm
Torque is obtained when force is multiplied with the distance
As the force is conserved we have
[tex]\dfrac{20}{30}\times 30=20\ cm[/tex]
The distance will be 20 cm to the right of the center or 20+50 = 70 cm from the left side.
