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Question 8(Multiple Choice Worth 1 points) (04.03 LC) Given the following system of equations:
−4x + 8y = 16
2x + 4y = 32
What action was completed to create this new equivalent system of equations? −2x + 4y = 8
2x + 4y = 32
A) Divide the second equation, 2x + 4y = 32, by 2.
B) Divide the first equation, −4x + 8y = 16, by 2.
C) Multiply the second equation, 2x + 4y = 32, by −1.
D) Multiply the first equation, −4x + 8y = 16, by −1.

Respuesta :

calculista

Answer:

Option B) Divide the first equation, −4x + 8y = 16, by 2

Step-by-step explanation:

we have

[tex]-4x+8y=16[/tex] ----> First equation

[tex]2x+4y=32[/tex] ----> Second equation

Divide the first equation by 2 both sides

so

[tex]\frac{1}{2}(-4x+8y)=\frac{1}{2}(16)[/tex]

apply distributive property left side

[tex]\frac{1}{2}(-4x)+\frac{1}{2}(8y)=\frac{1}{2}(16)[/tex]

[tex]-2x+4y=6[/tex]

The new equivalent system is

[tex]-2x+4y=6[/tex] ---> first equation divided by 2

[tex]2x+4y=32[/tex] ---> is the same second equation

therefore

Option B

Answer:

Divide the first equation, −4x + 8y = 16, by 2.

Step-by-step explanation:

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