Answer:
The necessary equations necessary are explained in each step in the solution.
Explanation:
For conversion of methanol gas at 65°C to -112°C
the equations would be as follows,
step 1 : gas at 65°C to liquid at 65°C
q = n(-37 kJ/mol)
step 2 : liquid at 65°C to liquid at -94°C
q = n(81.1 J/mol°C), where dT is negative
step 3 : liquid at -94°C to solid at -94°C
q = n(-3.18 kJ/mol)
step 4 : solid at -94°C to solid at -112°C
q = n(48.7 J/mol°C), where dT is negative
