Answer:
C) 160 N
Explanation:
[tex]m[/tex] = mass of the car = 2000 kg
Weight of the car is given as
[tex]W = mg \\W = (2000) (9.8)\\W = 19600 N[/tex]
[tex]F_{i}[/tex] = Force exerted on the input piston
[tex]A_{i}[/tex] = Area of input piston = 10 cm x 10 cm = 0.1 m x 0.1 m = 0.01 m²
[tex]A_{lift}[/tex] = Area of lift = 1 m x 1.2 m = 1.2 m²
Using Pascal's law
[tex]\frac{F_{i}}{A_{i}} = \frac{W}{A_{lift}}\\\frac{F_{i}}{0.01} = \frac{19600}{1.2}\\F_{i} = 160 N[/tex]
