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Two toy cars (16kg and 2kg) are released simultaneously on aninclined plane that makes an angle of 30` with the horizontal.Which statement best describes their acceleration after beingreleased? and why?
A) The 16-kg car accelerates 8 times faster than the 2-kgcar.
B) The 2-kg car accelerates 8 times faster than the 16-kgcar.
C) Both cars accelerate at a rate of (0.87)g.
D) Both cars accelerate at a rate of (0.50)g.

Respuesta :

Answer:

D

Explanation:

On an inclination of 30°, the acceleration down the inclination will be gsinФ. So the acceleration will be  ⇒

                        g Sin30° = (0.50) g

okpalawalter8

There accelerations are is mathematically given as

a=8m/s^2

a=1m/s^2

and also

a=(0.5)g

Hence, The 16-kg car accelerates 8 times faster than the 2-kg car and Both cars accelerate at a rate of (0.50)g. are correct Option A, D

What is the acceleration of the car?

Question Parameters:

Two toy cars (16kg and 2kg)

an inclined plane that makes an angle of 30`

Generally, the equation for the Accelartion  is mathematically given as

a=g sin \theta

Therefore

For 16g

a=g sin \theta

a=16 sin 30

a=8m/s^2

For

For 2g

a=g sin \theta

a=2 sin 30

a=1m/s^2

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