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The real numbers a and b are such that the discriminant of the quadratic [f(x) = ax^2 - bx - 16]is less than or equal to 0. Find the largest possible value of 4a - b.

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erolkayacan

Answer:

The answer is 4.

Explanation:

[tex]f(x)=a*x^{2} -b*x-16\leq 0\\a*x^{2} -b*x\leq 16\\(a*x-b)*x\leq 16[/tex]

When we put 4 instead of x, the equation will be:

[tex](4a-b)*4\leq 16\\(4a-b)\leq 4[/tex]

Find the largest possible value of 4a - b is 4

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