Consider this scenario: For each year t, the population of a forest of trees is represented by the function A(t) = 113(1.029)t. In a neighboring forest, the population of the same type of tree is represented by the function B(t) = 81(1.025)t.

Which forest's population is growing at a faster rate?

Respuesta :

Answer:

The forest A is growing at a faster rate as it has a larger base (1.029).

Step-by-step explanation:

We have been given that for each year t, the population of a forest of trees is represented by the function [tex]A(t)=113(1.029)^t[/tex]. In a neighboring forest, the population of the same type of tree is represented by the function [tex]B(t)=81(1.025)^t[/tex].

We know that an exponential growth function is in form [tex]y=a\cdot b^x[/tex], where,

y = Final value,

a = Initial value,

b = For growth base b is in form [tex](1+r)[/tex], where r represents rate in decimal form,

x = Time.

We know that the larger the base of an exponential function would be, the larger will be growth rate.

Upon looking at both functions, we can see that base of function [tex]A(t)=113(1.029)^t[/tex] is 1.029 and base of function[tex]B(t)=81(1.025)^t[/tex] is 1.025.

Since 1.029 is greater than 1.025, therefore, the forest population represented by function [tex]A(t)=113(1.029)^t[/tex] grows at a faster rate.