Answer:
kE=0.0735 J
Explanation:
Given that
Radius ,R=10 cm = 0.1 m
Mass ,m= 3 kg
Angular speed ,ω = 3.5 rad/s
We know that moment of inertia for solid sphere given as
[tex]I=\dfrac{2}{5}mR^2[/tex]
Kinetic energy
[tex]KE=\dfrac{1}{2}I\omega^2[/tex]
Now by putting the values
[tex]KE=\dfrac{1}{2}\times \dfrac{2}{5}mR^2\times \omega^2[/tex]
[tex]KE=\dfrac{1}{2}\times \dfrac{2}{5}\times 3\times 0.1^2\times 3.5^2\ J[/tex]
kE=0.0735 J
Therefore the kinetic energy will be 0.0735 J
