A youngs's double slit has separation of 2.5 x 10-5 m on wich a monochromatic light bean is directed. the resultant bright fringes on the screen 1.0 fro the double slit are separated by 2.3 x 10-2 m.What is the wavelenght of this bean?

Respuesta :

Answer:

575 nm

Explanation:

The variables in the given problem are Δy, λ, L, and d. In order to estimate the wavelength of the beam, we can use the equation below:

Δy = λ*L/d

Where:

Δy is the space between the fringes which is equivalent to 2.3*10^-2 m.

λ is the unknown wavelength in m

L is 1.0 m

d is the separation of the young's double slit which is equal to 2.5*10^-5 m

Thus:

λ = Δy*d/L = (2.3*10^-2)*(2.5*10^-5)/1 = 575*10^-9 m = 575 nm

Therefore, the wavelength of the beam is 575 nm.