To solve this problem we will find the proportion in terms of the solution and solution. According to the data given, the amount of solute is 1,929g in a solution of 25,725g, therefore the mass / mass percentage would be:
[tex]\% m/m = \frac{g_{solute}}{g_{solution}} * 100[/tex]
Replacing,
[tex]\% m/m = \frac{1.929g}{25.725g}*100[/tex]
[tex]\% m/m = 7.499\%[/tex]
Therefore there is 7.499% of solute in the urine sample.
