Answer:
v=2.88 m/s
Explanation:
Given that
R= 0.85 m
The minimum speed of the bucket to prevent the water from falling out given as
[tex]v=\sqrt{Rg}[/tex]
Where
R=Radius of the circular arc
g=Acceleration due to gravity
We are taking g= 9.81 m/s²
Now by putting the values
[tex]v=\sqrt{Rg}[/tex]
[tex]v=\sqrt{0.85\times 9.81}\ m/s[/tex]
v=2.88 m/s
Therefore the speed of the bucket should be 2.88 m/s.
