Explanation:
Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184
Then, the stations N share 56 kbps
And, the channel rate = [tex]0.184*56[/tex] [tex]= 10.304 kbps.[/tex]
Then, the outputs of the wach stations is [tex]1000-bit frames/100 sec[/tex]
[tex]\therefore[/tex], the output of the bits/ sec by each stations = [tex]\frac{1000}{100} bits/sec = 10 bits/sec[/tex]
So, The output of the N stations is 10 bits/sec on the channel that having [tex]10.304kb/sec[/tex]
Finally, N = [tex]\frac{(10.304 \times 10^{3})}{10} = 1030 stations[/tex]