Answer:21.18 m
Explanation:
Given
initial speed u=10 m/s
height of building h=22 m
time taken to complete 22 m
[tex]h=ut+\frac{1}{2}at^2[/tex]
initial vertical velocity =0
[tex]22=\frac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\frac{22\times 2}{g}}[/tex]
[tex]t=2.11 s[/tex]
Horizontal Distance moved
[tex]R=u_x\times t[/tex]
[tex]R=10\times 2.11[/tex]
[tex]R=21.18 m[/tex]
