Answer:
(a)The volume of the iron anchor = 25.2 m³
(b)The mass of iron = 196812 kg
Explanation:
Density: This is the ratio of the mass of a body to its volume. The S.I unit of density is kg/m³
(a)
From Archimedes principle, the iron will displace a volume of water that is equal to its volume. And the weight of water displaced is equal to loss in weight or upthrust.
Therefore, Upthrust = lost in weight = weight of water displace.
Therefore, Volume of the iron = mass of water displace/density of water
Vi = m₁/D₁........................... Equation 1
Where Vi = volume of iron, m₁ = mass of water displaced, D₁ = Density of water.
Given: upthrust = 252 N, ∴ m₁ = 252/10 = 25.2 kg.
Constant: D₁ = 1.0 kg/m³
Substituting these values into equation 1,
Vi = 25.2/1.0
Vi = 25.2 m³
Therefore the volume of the iron anchor = 25.2 m³
(b)
Density of the iron = mass of the iron/volume of the iron.
Therefore, Mass of the iron = Density of the iron × volume of the iron...........................................equation 2
Given: Density of the iron = 7810 kg/m³, Volume of the iron = 25.2 m³
Substituting these values into equation 2,
Mass of the iron = 7810×25.2
Mass of the iron = 196812 kg.
Therefore the mass of iron = 196812 kg
