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The magnetization curve of a shunt connected DC motor is linear and is given by EA=(82 V/A) IF when measured at a speed of 1,710 rpm. The motor has RA = 9Ω , Radj = 6Ω , and RF = 30Ω. A voltage of VT = 97 V is applied to the motor. What is Kϕ for the motor in Wb?

Respuesta :

Answer:

K ∅ = 1.48 Wb

Explanation:

given data

EA=(82 V/A)

speed = 1,710 rpm

RA = 9Ω

Rad j = 6Ω

RF = 30Ω

voltage VT = 97 V

to find out

Kϕ for the motor in Wb

solution

first we get here shunt field current

shunt field current  = [tex]\frac{VT}{RF}[/tex]   ............1

shunt field current  = [tex]\frac{97}{30}[/tex]

shunt field current  IF = 3.233 A

and

now we get here induced emf for field current that is

induced emf = 82  IF

induced emf = 82 × 3.233

induced emf =  265.133 V

and induced emf EA is also express as

induced emf EA = K∅ω   .....................2

EA = K ∅ × [tex]\frac{2\pi N}{60}[/tex]

put here value

265.133 = K ∅   × [tex]\frac{2\pi *1710}{60}[/tex]

solve we get

K ∅ = 1.48 Wb

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