Answer:
Specific heat capacity = 0.24 j/g.°C
Explanation:
Given data:
Mass of metal = 82.4 g
Heat absorbed = 846 j
Change in temperature = 67°C - 25°C
Specific heat capacity = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 67°C - 25°C
ΔT = 42°C
Q = m.c. ΔT
846 j = 82.4 g . c. 42°C
c = 846 j / 3460.8 g.°C
c = 0.24 j/g.°C
