Respuesta :
Answer:
Work function of the metal is 3.24 eV.
Explanation:
It is given that,
Wavelength, [tex]\lambda=383\times 10^{-9}\ m[/tex]
Let W is the work function of the metal. It is given by using Einstein's photoelectric effect equation. It is given by :
[tex]W=\dfrac{hc}{\lambda}[/tex]
[tex]W=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{383\times 10^{-9}}[/tex]
[tex]W=5.193\times 10^{-19}\ J[/tex]
Since, [tex]1\ eV=1.6\times 10^{-19}\ J[/tex]
So, W = 3.24 eV
So, the work function of the metal is 3.24 eV. Hence, this is the required solution.
Answer:
5.19 x 10^-19 J
Explanation:
threshold wavelength, λo = 383 nm = 383 x 10^-9 m
Work function,
[tex]\phi =\frac{hc}{\lambda _{0}}[/tex]
[tex]\phi =\frac{6.63\times10^{-34}\times 3 \times 10^{8}}{383\times 10^{-9}}[/tex]
Ф = 5.19 x 10^-19 J
