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A crate slides down a ramp that makes a 20o angle with the ground. To keep the crate moving at a steady speed, Paige pushes back on it with a 68 N horizontal force. How much work does Paige do on the crate at is slides 3.5 m down the ramp?

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Answer:

-223.64684 J

Explanation:

F = Force that is applied to the crate = 68 N

s = Displacement of the crate = 3.5 m

[tex]\theta[/tex] = Angle between the force and displacement vector = (180-20)

Work done is given by

[tex]W=Fscos\theta\\\Rightarrow W=68\times 3.5\times cos(180-20)\\\Rightarrow W=-223.64684\ J[/tex]

The work that Paige does on the crate is -223.64684 J

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