zarzar1
contestada

Find three positive consecutive even integers such that the product of the first and second is 8 more than 38 times the third
The three integers, in ascending order, are ___, ____, and____

Respuesta :

Answer:

40, 42, 44

Step-by-step explanation:

x, x+2, x+4 are the 3 positive consecutive integers.

x(x+2)=8+38(x+4)

x^2+2x=8+38x+152

x^2+2x-38x-8-152=0

x^2-36x-160=0

(x-40)(x+4)=0.

x-40=0

x=40 1st integer.

40+2=42 2nd integer.

40+4=44 3rd integer.

Proof:

40*42=8+38*44

1680=8+1672

1680=1680.

Best of Luck to you.

If you have any questions, feel free to comment below.

Have a Happy New Year.