Answer:
∅=2021rad
Explanation:
Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) i the light from the two slits at an angle of 28.0 ∘ from the centerline?
A wave is a disturbance which travels through a medium, it transfers energy without a permanent displacement of the medium itself. this is an example of light wave
using the formula below
∅=[tex]\frac{2\pi*d }{\beta } sin\alpha[/tex]
the phase difference is given from the above
d= distance/separation of slits .00037m
[tex]\beta[/tex]=wavelength
540*10^-9m
[tex]\alpha[/tex]=angle of two slits 28.0 ∘
∅=([tex]\frac{2\pi*0.00037 }{540*10^-9} sin 28[/tex]
∅=2021rad
there are large bright fringes from the centre line