Answer:
0.021 kgm/s
Explanation:
using energy
change potential energy of the egg = change in kinetic energy of the egg
mgh = 1/2 mv² m in kg, h in meters
5.0g = 5.0/1000 kg= 0.005 kg
90 cm = 90 / 100 = 0.9 m
cancel m on both side
gh = 1/2 v²
make v subject of the formula
v = √2gh = √2×9.81×0.9 = √17.658 = 4.2 m/s that is the velocity of the egg on impact with floor and the initial velocity of the egg is zero.
impulse = m × Δv = 0.005 × 4.2 = 0.021 kgm/s
