Answer:
mvoh Cosθ
Explanation:
Velocity of projection = vo
Angle of projection = θ
acceleration due to gravity = g
Range = R
Maximum height = R
At highest point, the velocity has only horizontal component which always remains constant = vo Cosθ
At maximum height
linear momentum = mass x velocity = m vo Cos θ
Angular momentum = linear momentum x perpendicular distance
Lo = m x vo x Cos θ x h
Lo = mvoh Cosθ
Thus, the angular momentum about O is mvoh Cosθ.