A student in an undergraduate physics lab is studying Archimede's principle of bouyancy. The student is given a brass cylinder and, using a triple beam balance, finds the mass to be 2.23 kg. 2.23 kg. The density of this particular alloy of brass is 8.44 g/cm 3 . 8.44 g/cm3. The student ties a massless string to one end of the cylinder and submerges it into a tank of water where there is an apparent reduction in the weight of the cylinder. With this information, calculate the volume, V , V, of the cylinder and the tension, T , T, in the string when it is submerged in the tank of water. The density of water is 1.00 g/cm 3 , 1.00 g/cm3, and the acceleration due to gravity is g

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moya1316 moya1316 · Answer 1 · 2019-12-01T13:26:30+01:00

Answer:

V = 2.64 10⁻⁴ m³, T = 21.85 N , T = 19.26 N

Explanation:

To calculate the cylinder volume we use the density equation

ρ = m / V

V = m / ρ

ρ = 8.44 g / cm³ (1 kg / 1000g) (10² cm / 1m)³ = 8.44 10³ kg / m³

V = 2.23 / 8.44 10³

V = 2.64 10⁻⁴ m³

We calculate the tension with Newton's second law

In the air

T-W = 0

T = mg

T = 2.23 9.8

T = 21.85 N

In water

In this case we have the push up

T + B -W = 0

T = W -B

The push formula is

B = [tex]\rho_{water}[/tex] g V

T = m g - [tex]\rho_{water}[/tex] g V

T = 2.23 9.8 - 1.00 103 9.8 2.64 10-4

T = 21.85 - 2.5872

T = 19.26 N